555; 55555; 5555555;... In this arrangement of numbers, how many 5's are there in
the 25th number?
Answers
Answered by
0
Answer:
555555555555555555555555555555555555555555555555555
Step-by-step explanation:
51
PLEASE MARK ME BRAINLIEST.
Answered by
0
Answer:
51
Step-by-step explanation:
By the arithmetic prorogation formula
A= 555's number of digits=3
N=Total number of times 5's have to be repeated=25
T=Total number of 5 increased in each expression=2
A+(N-1)*T=
3+(25-1)*2=
51
Similar questions