Question

adjacent figure is triangular in shape and is semi circular at the bottom .find the total area of this figure

• Don't spam
• Need quality answer

All the best​

Answer 1

Answer:

answer for the given problem is given

Step-by-step explanation:

Answer 2

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Let's \: understand \: the \: question \: first:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

This is a question of Mensuration In which an adjacent figure is given which is

• Triangular in shape

• Semi circular at the bottom

And we need to find the total area of this figure .

Let's solve it !!

______________________________________

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Answer:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

• 104.52 m²

______________________________________

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Given:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

Adjacent figure is

• Triangular in shape

• Semi Circular at the bottom

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{To \: find:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

• Total area of this figure

Therefore, Total area of given figure = Area of triangle + Area of semicircle

______________________________________

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Solution:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

before finding the answer first we need to find the height of the triangle ( as shown in the attachment )

Height + Base = Hypotenuse

OA² + AB² = OB²

OA² + 6² = 10²

OA² + 36 = 100

OA² = 100-36

OA = √64

OA = 8 m

Now , Area of triangle ( ∆ OBC )

$\longrightarrow \sf \dfrac{1}{2 } \times OA \times CB$

$\longrightarrow \sf \dfrac{1}{2 } \times 8 \times 12$

$\longrightarrow \sf 48 {m}^{2}$

Now Area of semi circle

$\longrightarrow \sf \dfrac{1}{2 } \times \pi \times {6}^{2}$

$\longrightarrow \sf \dfrac{1}{2 } \times 3.14\times 36$

$\longrightarrow \sf 56.52 {m}^{2}$

Now , we know that

Total area of given figure = Area of triangle + Area of semicircle

Total area of given figure = 48m² + 56.52m²

Total area of given figure = 104.52m²

______________________________________

$\begin{gathered} \begin{gathered} \begin{gathered}\begin{gathered}\\\;\underbrace{\underline{\sf{Know \: More:-}}}\end{gathered}\end{gathered} \end{gathered} \end{gathered}$

⠀

$\begin{gathered}\\\;\sf{\leadsto\;\;\purple{Rectangle}}\end{gathered}$

• Perimeter = 2 ( l × b )

• Area = l × b

• Diagonal = √ l² + b²

⠀

$\begin{gathered}\\\;\sf{\leadsto\;\;\purple{Square}}\end{gathered}$

• Perimeter = 4a

• Area = a × a = a²

• Diagonal = √ a² + a² = √2a² = √2a

⠀

$\begin{gathered}\\\;\sf{\leadsto\;\;\purple{Parallelogram}}\end{gathered}$

• Perimeter = 2 ( sum of two adjacent sides )

• Area = b × h

⠀

$\begin{gathered}\\\;\sf{\leadsto\;\;\purple{Triangle}}\end{gathered}$

• Perimeter = a + b + c

• Area = ½ × b × h

⠀

$\begin{gathered}\\\;\sf{\leadsto\;\;\purple{Circle}}\end{gathered}$

• Perimeter = circumference = 2πr

• Area = πr² , where r = 22/7

• Diameter = 2r