Math, asked by sunilatha1998, 5 months ago

56.
Find the LCM of the polynomials:
90(x - 5x+6)(2x + 1)' and 140(x-3) (2x15x + 7)
(A) 1260(x-2)(x - 3)(2x + 1)(x + 7) (B) 1260(x-2)(x + 2) (2x + 1)(x + 7)
(C) 1260(x - 2)(x - 3) (2x + 1)(x7) (D) 1260(x - 2)(x - 3)' (2x - 1)(x + 7)​

Answers

Answered by khashrul
3

Answer:

L.C.M  =1260(x - 2)(x - 3)(x + 7)(2x + 1)

Option (A) is correct Answer.

Step-by-step explanation:

90(x^2 - 5x + 6)(2x + 1)

=90(x^2 - 2x - 3x + 6)(2x + 1)

=90(x - 2)(x - 3)(2x + 1)

And 140(x - 3)(2x^2 + 15x + 7)

=140(x - 3)(2x^2 + x + 14x + 7)

=140(x - 3)(2x + 1)(x + 7)

L.C.M =10.9.14(x - 2)(x - 3)(x + 7)(2x + 1) =1260(x - 2)(x - 3)(x + 7)(2x + 1)

Option (A) is correct Answer.

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