Question

56. The amount of heat to be removed from
10 gm water at 0°C to convert it into ice
is (Lice = 80 cal/gm)​

Answer 1

Answer:

Heat supplied is Lfusion + McΔ T + MLvap Q1 = 10 × 336 + 10 × 4.2 × 100 + 10 × 2260 Q1 = 30160 J or 7200 cal Heat for calorimeter Q2 = 10 × 1