Question

57. Two small spheres of masses 10kg and 30 kg
are joined by a rod of length 0.5 m and of
negligible mass. The M.I of the system about
a normal axis through centre of mass of the
system is​

Answer 1

Answer:

The answer is 2.5 kgm^2

Explanation:

Given Data:

m1 = 10 Kg

m2 = 30 Kg

Length "l" = 0.5 m

The M.I. of the system about a normal axis through centre of the system is

I = m1r12 + m2r22

 = 10 x (0.25)2 + 30 x (0.25)2

 = 40 x (0.25)2  

 = 2.5 kg.m^2