57. Write the molecular orbital configuration of the following species: a) N2, N2+, N2-, N22- b) O2, O2-, O2+, O22+
i. Calculate their bond order.
ii. Predict their magnetic behavior.
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Answer:
Bond order =
2
1
[N
b
−N
a
]
N
b
= number of bonding electrons
N
a
= number of anti-bonding electrons
→ Bond order of N
2
is 3
→ Bond order of N
2
−
is 2.5
→ Bond order of N
2
+
is 2.5
Bond order α stability α
bondlength
1
order of bond length
Ans :- N 2+=N 2->N 2
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