Question

5765x4y is divisible by 9. What is the maximum number of values that x can take for any particular value of y

Answer 1

Step-by-step explanation:

Given 5765x4y is divisible by 9. What is the maximum number of values that x can take for any particular value of y

• Now sum of the digits will be 5 + 7 + 6 + 5 + x + 4 + y
•                                          = 27 + x + y
• Now 27 is divisible by 9, so we need to check divisibility of x and y
• If the number is divisible then it is divisible by 9 or x + y = 0
• Then x = 0, y = 0
• But we need to find the maximum value of x
• If x + y = 18

Then x = 9, y = 9