Question

58. Two soap bubbles of radii 4cm and, 5em
coalesce to form a common surface. The
radius of curvature of this common
surface will be​

Answer 1

Answer:

The excess pressure inside any soap bubble is given by the expression,

P excess = 4T/t

P¹ = 4T/4

P² = 4T/5

The difference between the 2 pressures will account for the radius of the new surface.

P¹ - P² = 4T/t

4T/4 - 4T/5

Solving, gives r = 20 cm