Question

find the value of x in adjoining figure ​

Answer 1

x-10+2x+10+40= 180

3x+40=180

3x= 140

x= 45

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Answer 2

Answer:

$\sf{(x - 10)°} + \sf{(2x + 10)°} + \sf{40°} = \sf{180°}$

{Angle in a straight line is 180°}

$\sf{(3x + 40)°} = \sf{180°}$

$\sf{3x} = \sf{180°} - \sf{40°}$

$\sf{3x} = \sf{140°}$

$\sf{x} = \sf (\frac{140}{3})°$