Math, asked by dilnawaj, 11 months ago

59×59×59-9×9×9/59×59+59×9+9×9=50

Answers

Answered by prakash3390
15
50 is the answer hope it will help you
Answered by MOSFET01
25
59=a

9= b

(a³-b³)= (a-b)(a²+ab+b²)

59³-9³/59²+59×9+9²

(59-9)(59²+59×9+9²)/(59²+59×9+9²)

substitute

(59-9)

(50)

LHS= RHS
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