Question

59. A motor pumps water at the rate of V m3 per
second, against a pressure P Nm-2. The power of
the motor in watt is
1) PV
2) P/V
3 V/P
-
4) (V-P)



60. If the units of length and force are increased by
four times the unit of energy will be increased by
1) 16% 231600% 3)1500% 4) 400%​

Answer 1

Answer:

Rate of pumping water =Vm

3

/s

Pressure applied =PN/m

2

Power is defined by =

time

workdone

as work done = pressure × change in volume (w=PΔV)

power =P× (Rate of ΔV )

power =PV

Explanation:

I hope that this answer help you!