Question

If alpha and beta are zeroes of quadratic equation f(x)= ax^2+bc+c then evaluate,
(1/alpha) - (1/beta)

Answer 1

❔F(x)= ax²+bx+c

❓(1/alpha)-(1/beta)=❔

➡️(1/alpha)-(1/beta)

➡️ CROSS MULTIPLYING:-

➡️Beta-Alpha/alpha× beta

➡️-(alpha+beta)/alpha×beta

➡️-(-b/a)/(c/a). [since alpha+beta=- b/a and alpha beta= c/a]

➡️b/c..