595and 252 how to find hcf
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Answered by
0
594= 252*2+48
252= 48*2+ 12
= 48= 12*4+0
so,hcf= 12
252= 48*2+ 12
= 48= 12*4+0
so,hcf= 12
Answered by
0
just use Euclid's division lemma
a = bx + r ...( B > r )
594= 252*2+48
252= 48*2+ 12
= 48= 12*4+0
12 divided it with no r remaining
hence 12 is the hcf.
hoping it helps
thanks....
a = bx + r ...( B > r )
594= 252*2+48
252= 48*2+ 12
= 48= 12*4+0
12 divided it with no r remaining
hence 12 is the hcf.
hoping it helps
thanks....
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