For what value of k does (k,-3) lies on 3x-y=6
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the value of k is " 0 "......
(k,-3) x=k, y=-3
3x-y=6
3(k)-(-3)=3
3k+3=3
3k=0
k=0
(k,-3) x=k, y=-3
3x-y=6
3(k)-(-3)=3
3k+3=3
3k=0
k=0
Answered by
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The value of k=0
(0,-3)
(0,-3)
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