Question

5a³-9a²b-9ab² divided by -3a²​

Answer 1

Answer:

$=-\frac{5a^2-9ab-9b^2}{3a}$

Step-by-step explanation:

$\frac{5a^3-9a^2b-9ab^2}{-3a^2}$

$=\frac{a\left(5a^2-9ab-9b^2\right)}{-3a^2}$

$=\frac{a\left(5a^2-9ab-9b^2\right)}{-3aa}$

$=\frac{5a^2-9ab-9b^2}{-3a}$

$=-\frac{5a^2-9ab-9b^2}{3a}$

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