Math, asked by Mingyurpaldon9517, 1 year ago

5A6 is a number divisible by '2' then write all possible value of a

Answers

Answered by ticks4ticks5pd2u3q
5

Answer:  " a = 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 ".

Since, if a number is even, or ends in zero, the number is divisible by "2" .

If the last digit of a number is an "even number" , the entire number is an even number.

As such:  If the last digit of the number is an even number, then the last number is divisible by "2" .

Also, note that if the last digit of a number is "0" , then the number is divisible by "2" .

So:  If the last digit of a number is "0" or an "even number" (i.e. "2, 4, 6, or 8" ), then the number is divisible by "2" .


Given:  The number:  " 5A6 " ;  we note the number ends in "6" ; which is an "even number" .  The middle digit, "A" , could be any digit:  "0, 1 , 2, 3, 4, 5, 6, 7, 8 , or 9 " ) ;  because the the last digit in the given number is still "6" ; which is an even number ; so entire number:  "5A6"  will be an even number; regardless of what digit, "A", is , and the number will still be divisible (evenly) by "2" .

As such:  "A" could be:  "0, 1, 2, 3, 4, 5, 6, 7, 8, or 9" .

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In fact:

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If  "a = 0" :   then:  " 5A6 " =  " 506 " ;   506 ÷2 = 253 .

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If  "a = 1" :   then:  " 5A6 " =  " 516 " ;    516 ÷2 =   258 .

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If  "a = 2" :   then:  " 5A6 " =  " 526 " ;   526 ÷2 = 263 .

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If  "a = 3" :   then:  " 5A6 " =  " 536 " ;   536 ÷2 = 268 .

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If  "a = 4" :   then:  " 5A6 " =  " 546 " ;   546 ÷2 = 273 .

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If  "a = 5" :   then:  " 5A6 " =  " 556 " ;   556 ÷2 = 278 .

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If  "a = 6" :   then:  " 5A6 " =  " 566 " ;   566 ÷2 = 283 .

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If  "a = 7" :   then:  " 5A6 " =  " 576 " ;   576 ÷2 = 288 .

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If  "a = 8" :   then:  " 5A6 " =  " 586 " ;   586 ÷2 = 293 .

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If  "a = 9" :   then:  " 5A6 " =  " 596 " ;   596 ÷2 = 298 .

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Hope this answer is helpful to you!

Best wishes!

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ticks4ticks5pd2u3q: Thank you! Glad I could be of help. I look forward to participating within the "Indian" Brainly community! And likewise, a warm 'reciprocal welcome' — for lack of a better phrase — to you and the "Indian Brainly community" and all fellow members within!
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