Math, asked by cchandio040, 1 year ago

5c(c+1)=0 solve this quadratic equation plzzzzzzzzzzzz

Answers

Answered by Anonymous
3

Answer:

5c(c + 1) = 0 \\  \\ c + 1 =  \frac{0}{5c}  \\  \\ c + 1 = 0 \\  \\ c =  - 1

Answered by sreedeviaddepal
0

Answer:

0 or  -1

Step-by-step explanation:

If (x-a)(x-b) =0 then either (x-a) =0 or   (x-b) =0

Basing on the above , either 5c =0 or c+1 =0

if 5c =0 then c=0

if c+1=0 then c =-1

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