5c(c+1)=0 solve this quadratic equation plzzzzzzzzzzzz
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3
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0
Answer:
0 or -1
Step-by-step explanation:
If (x-a)(x-b) =0 then either (x-a) =0 or (x-b) =0
Basing on the above , either 5c =0 or c+1 =0
if 5c =0 then c=0
if c+1=0 then c =-1
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