5cosθ=12sinθ find (sinθ+cosθ)/(2cosθ-sinθ)
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Solution ___✌️✌️
5 cosA=12 SinA
5/12=tanA
Now make a triangle whose altitude is 5 and base is 12
So, by pythagoras ___
Hypo=13
SinA=5/13
CosA=12/13
Now,
SinA+cosA=5/13+12/13=17/13
2cosA-sinA=24/13-5/13=19/13
Now,
SinA+cosA/2cosA-sinA=17/13*13/19
=17/19
Note__☺️
I use 'A' instead of theta____
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