Question

The length of a rectangle is 5 m greater than its width. If the perimeter of the rectangle is 50m find its length

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Answer 1

$\hugeᎡҽբҽɾ \: \: Եհҽ \: \: αԵԵαcհᎷҽղԵ \: \: Ꮲlz$

Let it's length be l and width be w , then

According to question:

l = 2w+5 - eq.n(1) , then ,

Area = l×w

75=(2w+5)×w

75=2w^2+5w

2w^+5w-75=0

taking it's roots,

2w^2+15w-10w-75=0

w(2w+15)-5(2w+15)=0

(2w+15)(w-5)=0

w = -15/2(not possible as width cannot be negative)

so, w = 5 units

Now,

Length=2w+5

=(2×5)+5

Length=15 units

Therefore our perimeter will be,

Perimeter =2(l+w)

=2(15+5)

Perimeter=40 units