Question

5cos²60°+ 4sin²30° + tan²45° ÷ sin²30° + cos²45°

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Answer 1

Answer:

13 / 2

Step-by-step explanation:

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Answer 2

$\huge\bold\blue{♡Áńśwéŕ♡}$

$\tt{ \frac{5cos²60°+ \: 4sin²30° + \: tan²45°}{ sin²30° + \: cos²45°}}$

$\longmapsto\tt { \frac{5( { \frac{1}{2} )}^{2} + \: 4 ( { \frac{1}{2}) }^{2} - {1}^{2} }{ ({ \frac{1}{2} })^{2} + { \frac{1}{ \sqrt{2} } }^{2} } }$

$\longmapsto\tt{ \frac{ \frac{5}{4} + 1 - 1}{ \frac{1}{4} + \frac{1}{2} }}$

$\longmapsto\tt { \frac{5}{4} ÷ \frac{3}{4}}$

$\longmapsto\tt { \frac{5}{\cancel {4}} \times \frac{\cancel {4}}{3}}$

$\longmapsto\tt\red { \frac{5}{3}}$