5cosx+12sinx=13then x value
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5cosx + 12sinx = 13,
5 + 12tanx = 13secx,
Squarin both-sides,
25 +144tanx^2 +120tanx = 169sec^2x=169(tan^2x +1),
25(tanx)^2 - 120tanx + 144 = 0,
(5tanx - 12)^2 = 0,
tanx = 12/5
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5 + 12tanx = 13secx,
Squarin both-sides,
25 +144tanx^2 +120tanx = 169sec^2x=169(tan^2x +1),
25(tanx)^2 - 120tanx + 144 = 0,
(5tanx - 12)^2 = 0,
tanx = 12/5
Hope it helps u
Plz mark as brainliest
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