5cot theta =7 then find 7sin theta + 5cos theta/ 5sin theta + 7cos theta
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given, 5 cot theta = 7.
Therefore, cot theta = 7/5.
Now, dividing the numerator and denominator of ( 7 sin theta + 5 cos theta ) / ( 5 sin theta + 7 cos theta ), i.e., ( 7 sin theta/sin theta + 5 cos theta/sin theta ) / ( 5 sin theta/sin theta + 7 cos theta / sin theta ), we get -----------
( 7 + 5 cot theta ) / ( 5 + 7 cot theta ) [ since, cos theta/ sin theta = cot theta]
= ( 7 + 5 * 7/5 ) / ( 5 + 7 * 7/5 )
= 35/37
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