5j-5i divided by 10=?
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j-y ÷2is the right answer
ankit523039:
no
why not
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Magnitude of 5j-5i is,
= √(5^2+ 5^2)
= 5√2 unit
After dividing by 10,
= (5√2)/10
= (1/√2)
Hence, (1/√2) is the correct answer.
kaise kiya?
5unit vector2+5unit vector2 kaise kiya
simply use Pythagoras theorem, in a rt. angled triangle Hypotenuse= √(perpendicular^2+base^2)
its (square of 5 + square of 5) under whole root.
2 kaise aaya
where
unit vector 2+base unitvector 2
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