Question

5j of work is done in moving a positive charge of 0.5 C between the two points.what is the potential difference between the two points?

Answer 1

$\textbf{Hey there}$!!

$\textbf{Answer}$:

Here work ($W_{AB}$) = 5 j

Charge($q_{0}$) = 0.5

The potential difference between the two points:

Now $V_{B}$ - $V_{A}$ = $\frac{W_{AB}}{q_{0}}$

= $\frac{5}{0.5}$

= 10 volt.

Be Brainly.

@karangrover12.

Answer 2

The potential difference between the two points is, 10 volt.

What is the potential difference between the two points?

• The potential difference between two points can be defined as the potential difference between two points is equal to the work done per unit charge in moving a positive test charge from one point to the other.
• It's S.I. unit is volt.

According to the question:

work $\left(W_{A B}\right)$ =5 j.

Charge$\left(q_{0}\right)$ =0.5.

The potential difference between the two points:

Now $V_{B}-V_{A}=\frac{W_{A B}}{q_{0}}$

$=\frac{5}{0.5}$

= 10 volt.

Hence, potential difference between the two points is, 10 volt.

Learn more about potential difference here,

https://brainly.in/question/19855900?msp_poc_exp=5

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