(5k+1) whole square is divisible by 5 _____ is reminder
Answers
Answered by
0
Step-by-step explanation:
-5 k is the remainder
Hope it helps you
Attachments:
Answered by
1
Answer:
(5k+1)^2
= (5k)^2 + 2*5k*1 + 1^2
= 25k^2 + 10k + 1
now, the terms 25k^2 and 10k are divisible by 5 for any value of k. But the term 1 is not divisible by 5 and is less than 5 also..
so the remainder will be 1
Similar questions