Question

For d - electron, the orbital angular momentum is
a)√2h / 2π
b)√2h / 4π
c)√2 X 4h / 2π
d)√6h / 2π
e)None of these
i will mark as brainliest if you say the correct answer

Answer 1

Answer :

Orbital angular momentum is given by

• OAM = √[l (l + 1)] h/2π

where, l denotes azimuthal quantum number of given orbital$.$

for s, l = 0

for p, l = 1

for d, l = 2

for f, l = 3

⇒ OAM = √[l (l + 1)] h/2π

⇒ OAM = √[2(2+1)] h/2π

⇒ OAM = √(2×3) h/2π

⇒ OAM = √6h/2π

Hence, (D) is the correct answer!

Answer 2

Answer :

Orbital angular momentum=

• $\sqrt{ {l \times (l + 1)} } \times \dfrac{h}{2\pi}$

For d subshell value of l(azimuthal quantum number) is 2

Thus by substituting l= 2 in the formula we get,

$\sqrt{l(l + 1)} \times \dfrac{h}{2\pi}$

$= > 2(2 + 1) \dfrac{h}{2\pi}$

$= > 2 \times 3 \dfrac{h}{2\pi}$

$\red{ = > 6 \times \dfrac{h}{2\pi}}$