5kg block is resting on a frictionless plane.It is struck by a jet releasing water at the rate of 3kg/s emerging with a speed of 4m/s .Calculate the initial acceleration of the block.
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2
Answer:
v=4m/s
dm/dt =3kg/s
a=?
we know that
F=v dm/dt
= 4×3
=12N
therefore a= F/m=12/5 = 2.4 m/s sq.
Answered by
1
Answer:
force of water =3kgs-¹*4ms-¹=12kgms-²
force exerted on bock=force of water
12=5*a
a=12/5=2.4ms-²
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