Question

the equation of projectile is y = ax - bx2 . its horizontal range is?​

Answer 1

Answer:

Range, R =\frac{a}{b}

Explanation:

Answer 2

Answer:

$\frac{a}{b}$

Explanation:

$y = ax - b {x}^{2} \\ y = x(a - bx) = 0 \\ x = 0 \: \: and \: \: \frac{a}{b}$

Value of y becomes zero twice . difference between these two points is horizontal range .

Range =

a/b