Physics, asked by manusuthar900, 10 months ago

5kg द्रव्यमान की एक वस्तु को किसी घर्षणहीन नत समतल पर रखी हुई
स्प्रिंग तुला से लटकाया गया है । स्प्रिंग तुला का पाठ्यांक होगा:
(g = 10 m/s)

Answers

Answered by Anonymous

3

उसके वज़न के समान होगा

इसलिए 5 × 10 = 50 Newton

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