Math, asked by Dikanku4986, 9 months ago

5m-3n=19 ; m-6n=-7 ( solve by substitution method

Answers

Answered by IITian20
2

Answer:

m= 5

n = 2

Step-by-step explanation:

5m-3n=19 ; m-6n=-7

m= -7 +6n

5(-7 +6n ) - 3n=19

-35+30n -3n = 19

27n = 54

n = 2

m= -7 +6(2)

m = 5

Answered by bsdurga5
3

Answer:

m,n=5,2

Step-by-step explanation:

5m-3n=19,------(1)

m-6n=-7 -------(2)

multiply (1)*1 and (2)*5

5m-3n=19

5m-30n=-35

(-)     (+)    (+)

------------------

     27n=54

      n=2

substitute n value in eq 2

m-6n=-7

m-6(2)=-7

m-12=-7=>-7+12

m=5

lets check it

substitute m,n values in any eq

m-6n=-7=>5-6(2)=-7

5-12=-7=>-7=-7

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