Question

5nd
pointon the x-axis which is equidiatance from the points A(6,5) and B(-4,3)​

Answer 1

Answer:

(4/5,0)

Step-by-step explanation:

let the poits be x,0

so

by distance formula we have

√{(6-x)^2+(5-0)^2 }= √{(-4-x)^2+( 3-0)^2}

squaring both sides

36+x^2-12x+25 = 16+x^2+8x+9

41 - 12x. = 25 + 8x

20x = 16

x= 16/20

x = 4/5