Math, asked by wwwDurgadutt19102002, 1 year ago

5p+q=2and 6p-3q=1
By elimination method

Answers

Answered by Anonymous
4

Answer:


Step-by-step explanation:

Hii

......

Gm..........

Acc to que eq 1 is multiply by3 and eq2 by 1

6p-3q=1

15p+3q=6

.......................

21p=7

P=1/3

Put the value in eq1

5p+q=2

5×1/3+q=2

5+3q=6

q=1/3

I HOPE THESE W ILL HELPS TO U

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Answered by aniketjadhao270
1

Answer:


5p+q=2..................1

6p-3q=1..................2


Multiply eqn 1 by 3

We get

15p+3q=6............1


Now adding,eqn 1 and 2 we get

21p=7

P=7/21

P=1/3


Putting value of p in equation 1

We get


5p+q=2

5*1/3+q=2

5/3+q=2

q=2-5/3

q=1/3




Therefor value of p=1/3


Value of q =1/3

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