Question

5p2 – 6q2 – 7r2 + 6p2 – 5q2 + 2r? if p is -1 q is ,q is 1, r is 2 simplify the expression and find their values
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Answer 1

Answer:

note: in such questions 1st we have to simplify the expression

so, 5p^2-6q^2-7r^2+6p^2-5q^2+2r

=5p^2+6p^2-6q^2-5q^2-7r^2+2r

=11p^2-11q^2-7r^2+2r

now putting the given values,

11(-1)^2-11(1)^2-7(2)^2+2(2)

11-11-28+4

=(-24)

Answer 2

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5p² – 6q² – 7r² + 6p² – 5q² + 2r? if p = -1 ,q = 1, r = 2, simplify the expression and find their values.

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$5p² – 6q² – 7r² + 6p² – 5q² + 2r$

$p = - 1 \\ q = 1 \\ r = 2$

$by \: substituting \: the \: values$

$= 5 {( - 1)}^{2} - 6 {(1)}^{2} - 7 {(2)}^{2} + 6 {( - 1)}^{2} - 5 {(1)}^{2} + 2(2)$

$= 5(1) - 6(1) - 7(4) + 6(1) - 5(1) + 2(2)$

$= 5 - 6 - 28 + 6 - 5 + 4$

$= 15 - 39$

$= - 24$

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