Question

5sin^2 30°- sin 90^° +2cous 0°/tan 30 ×2 tan60°​

Answer 1

Answer:

We have,

2sin30∘cos30∘+tan45∘5sin230∘+cos245∘−4tan230∘

=2×21×23+15×(21)2+(21)2−4×(31)2

=23+145+21−34

Step-by-step explanation:

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Answer 2

Answer:We have,

2sin30∘cos30∘+tan45∘5sin230∘+cos245∘−4tan230∘

=2×21×23+15×(21)2+(21)2−4×(31)2

=23+145+21−34

Step-by-step explanation: