Question

5t^2 + 6t - 36 = 0 Frnds, Please help me to find the value of 't' here.

Answer 1

hello mate!!


=> given

$5t {}^{2} + 6t - 36 = 0 \\ \\ this \: eq n \: is \: not \: possible \: to \: find \: roots \: .like \: this \: case \: we \: have \: t o \: use \: below \: formula.... \\ \\ x = \frac{ - b +or - \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ t = \frac{ - 6 + or- \sqrt{36 + 720} }{10} \\ \\ t = \frac{ - 6 + or - \sqrt{756} }{10} \\ \\ t = \frac{ - 6 + or \: - \sqrt{36 \times 21} }{10} \\ \\ t = \frac{ - 6 + or - 6 \sqrt{21} }{10} \\ \\ t = \frac{ - 6 + 6 \sqrt{21} }{10} \: and \: t = \frac{ - 6 - 6 \sqrt{21} }{10} \\ \\ t = \frac{ - 3 + 3 \sqrt{21} }{5} \: and \: t = \frac{ - 3 - 3 \sqrt{21} }{5} \\ \\ hope \: it \: helps \: u \: dear$