5t²-4t=2 quadrantic equation
Answers
Answer:
5
2
−
4
=
2
5t^{2}-4t=2
5t2−4t=2
5
2
−
4
−
2
=
0=
−
±
2
−
4
√
2
t=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
t=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
5
2
−
4
−
2
=
0
5t^{2}-4t-2=0
5t2−4t−2=0
=
5
a={\color{#c92786}{5}}
a=5
=
−
4
b={\color{#e8710a}{-4}}
b=−4
=
−
2
c={\color{#129eaf}{-2}}
c=−2
=
−
(
−
4
)
±
(
−
4
)
2
−
4
⋅
5
(
−
2
)
√
2
⋅
5
t=\frac{-({\color{#e8710a}{-4}}) \pm \sqrt{({\color{#e8710a}{-4}})^{2}-4 \cdot {\color{#c92786}{5}}({\color{#129eaf}{-2}})}}{2 \cdot {\color{#c92786}{5}}}
t=2⋅5−(−4)±(−4)2−4⋅5(−2)
3
Answer:
5t²-4t-2=0
Step-by-step explanation:
A Quadratic equation should have a square number , a variable and an integer so the answer is 5t²-4t-2=0...hope its useful