Question

5tan2A-5sec2A+1 is equal to​

Answer 1

Answer:

5tan

5tan 2

5tan 2 θ−5sec

5tan 2 θ−5sec 2

5tan 2 θ−5sec 2 θ

5tan 2 θ−5sec 2 θ⇒5(tan

5tan 2 θ−5sec 2 θ⇒5(tan 2

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan 2

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan 2 θ=sec

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan 2 θ=sec 2

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan 2 θ=sec 2 θ]

5tan 2 θ−5sec 2 θ⇒5(tan 2 θ−sec 2 θ)=5(−1)=−5 [∵1tan 2 θ=sec 2 θ]Hence, the answer is