Question

Anil wants to get an invested image of height
Bicm ig an object kept at l dustance of so.com
yram á concase mirror the focal length of the
mirror is 10cm At what distance form the
mituor should he flace the screen? What is the height
is the object ? (hint the height of the image should
Lbe taken as negative) ​

Answer 1

Answer:

Explanation:

whoa that's big but i will make it easy :)

height of the image = 5cm

u = - 30 cm ( object distance is always minus )

f = - 10 ( focal length of concave mirror is always minus )

using formula

1/f = 1/v + 1/u

we need image that is v so

1/v = 1/f - 1/u

1/v = 1/-10 - 1/-30

1/v = 30 - 10/ -300 = 20/-300

1/v = 1/-15

v = -15 ( cuz in concave mirror image is mostly formed on left side )

therefore the screen should be placed 15 cm away .

type of image is real and inverted

now

magnification = - v/u

15/30 = 1/2 = 0.5

so now

m = height of image / height of object

0.5 =  5/ height of object

therefore the height of object is 10 cm

the answer is a bit big but if u understood then no probs.