5th term of an A. P. is 17.Its 9th term is 35 more than the 2nd term. Find 20th term of the A. P.
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a + 4d = 17.................(i)
a + 8d = 35 + a + d
=> 8d - d = 35
=> 7d = 35
=> d = 5
Now, substitute d in eqn 1
a + 4(5) = 17
a = 17 - 20
a = -3
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Now,.
a + 19d
(-3) + 19(5)
-3 + 95
92
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#hope it help uh...
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