Question

5x 2 - 3x - 2 = о ( solve it by square root methode)​

Answer 1

Step-by-step explanation:

$Given 3x2−5x+2=0</p><p></p><p>Here, the coefficient of x2 is 3 and it is not a perfect square.</p><p></p><p></p><p>∴ Multiply the equation throughout by 3.</p><p></p><p></p><p>⇒(3x2−5x+2=0)×3∴9x2−15x+6=0</p><p></p><p>Now, half of the coefficient of x is 25.∴b=25 and b2=(25)2</p><p></p><p>So, 9x2−15x+(25)2−(25)2+6=0,(3x)2−15x+(25)2=(25)2−6</p><p></p><p>(3x−25)2=425−6=41</p><p>(Taking square root on both the sides)</p><p></p><p>∴3x−25=±21</p><p></p><p>∴3x−25=±21 or 3x−25=−21</p><p></p><p>3x=21+25          3x=25−21</p><p></p><p>3x=26=3            3x=24=2</p><p></p><p>∴x=1           x=32</p><p></p><p></p><p>$