Question

5x^2-4x+1=0 find the nature of the roots and solve​

Answer 1

We know that D = b^2 - 4ac

16 - 4( 5 )

16 - 20

= -4

D < 0

It means that the roots are imaginary , it doesn't have any real roots

Answer 2

Answer:

$here \: is \: ur \: answer \: dude$

${5x}^{2} - 4x + 1 = 0 \\ {5x}^{2} - 5x + 1x + 1 = 0 \\ 5x(x -1) - 1(x - 1) = 0 \\ (5x - 1)(x - 1) = 0 \\ x = 1 \: \: or \: \: 1 \div 5$

Step-by-step explanation:

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