Question

- p(x) = 3x + x² – 20x + 12, g(x) = 3x - 2​

Answer 1

Answer:

-20

Step-by-step explanation:

By using factor theorem

(3x−2)=0

3x=2

x=2/3

now, let f(x)=3x

3

+x

2

−20x+12

f(2/3)=3(2/3)

3

+(2/3)

2

−20(2/3)+12

f(2/3)=3(8/27)+(4/9)−(40/3)+12

f(2/3)=(8/9)+(4/9)−(40/3)+12

f(2/3)=(12/9)−(40/3)+12

f(2/3)=(4/3)−(40/3)+12

f(2/3)=12−(36/3)

f(2/3)=12−12

f(2/3)=0

(3x−2) is a factor of 3x

3

+x

2

−20x+12

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