5x^2 - 6x - 2 = 0 find the zeroes
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Answer:
5x^2 -6x -2 = 0
x^2 -(6/5)x -(2/5) = 0
(x)^2 - [2.(3/5).x] + (3/5)^2 - (3/5)^2 -(2/5) = 0
[x-(3/5)]^2 = (2/5)+(9/25)
[x-(3/5)]^2 = (19/25)
x-(3/5) = √19/5
x = (3/5) ± √19/5
Roots of the equation are
x = [3+(√19)]/5
& x = [3-(√19)]/5
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