5x^2+6x-8=0 find the nature of roots
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Heya !!!
5X² + 6X - 8 = 0
Here,
A = Coefficient of X² = 5
B = Coefficient of X = 6
And,
C = Constant term = -8
Discriminant (D) = B² - 4AC
=> (6)² - 4 × 5 × -8
=> 36 + 160
=> 196 > 0
Hence,
Discriminant of the given equation is greater than 0. so the roots of the given equation has real and equal .
★ HOPE IT WILL HELP YOU ★
5X² + 6X - 8 = 0
Here,
A = Coefficient of X² = 5
B = Coefficient of X = 6
And,
C = Constant term = -8
Discriminant (D) = B² - 4AC
=> (6)² - 4 × 5 × -8
=> 36 + 160
=> 196 > 0
Hence,
Discriminant of the given equation is greater than 0. so the roots of the given equation has real and equal .
★ HOPE IT WILL HELP YOU ★
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