Question

5x - 2 <= 3(3 - x) where x e {-2, -1, 0, 1, 2, 3, 4}

Answer 1

Answer:

5x-2=3(3-x)

5x-2=9-3x

8x=11

x=11/8

Answer 2

GIVEN:

$5x-2 ≤ 3(3-x)$

TO FIND:

Range of values of x.

ANSWER:

=>$5x-2 ≤ 3(3-x)$

=>$5x -2≤9-3x$

=>$5x + 3x ≤ 9+2$

=>$8 x ≤ 11$

=>$x ≤ \dfrac{11}{8}$

Hence x can satisfy values from -∞ to $\dfrac{11}{8}$

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$\huge\orange{\boxed{ x \:\epsilon (-∞,\dfrac{11}{8}]}}$

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But given that x belongs to -2,-1,0,1,2,3,4.

So, x can be -2,-1, 0&1 according to the condition found.

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$\huge\purple{\boxed{x\:\epsilon-2,-1,0,1}}$