Math, asked by nitinkumarrdx, 1 year ago

{(5x)^2x}^0=? plzz !!!!!it's urgent

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Answered by siddhartharao77
2
Given {(5x)^2x}^0.

( 5^{2x} *  x^{2x} } )^0

We know that a^n * b^n = a^n * b^n

( 5x^{2x})^0 * ( x^{2x})^0

(5)^{2x * 0}  *  (x)^{2x * 0}

 5^{0} *  x^{0}

1 * 1

1.


Hope this helps!
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