( 5x + 2y )^2 -- ( 2x + 5y )^2
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Answered by
1
Answer:
(5x+2y)^2-(2x+5y)^2
let use the formulae of (a+b)^2=a^2+b^2+2ab
<(5x)^2+(2y)^2+2*5x*2y> -<2x^2+5y^2+2*2x*5y>
<25x^2+4y^2+20xy>-<4x^2+25y^2+20xy>
25x^2+4y^2+20xy-4x^2-25y^2-20xy
25x^2-4x^2+4y^2-25y^2+20xy-20xy
21x^2-21y^2=0
take 21 common
21(x^2+y^2)=0 then,
x^2+y^2=0
Step-by-step explanation:
I hope it will be helpful
Answered by
0
Answer:
hey I thought it may help you
Step-by-step explanation:
now thake this equation as -
(a+b)²- (b+a)² now solve it
(5x)²+( 2y)² - (2x)² + (5y)²
25x²+4y² - 4x² + 25y²
now solve it
25x²+4x²+4y²-25y²=0
29x²- 21y²= 0
it would helpful to u and plezzz follow me for more helps
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