Math, asked by debanjanmukherjee30, 1 month ago

( 5x + 2y )^2 -- ( 2x + 5y )^2​

Answers

Answered by krishhhhnna
1

Answer:

(5x+2y)^2-(2x+5y)^2

let use the formulae of (a+b)^2=a^2+b^2+2ab

<(5x)^2+(2y)^2+2*5x*2y> -<2x^2+5y^2+2*2x*5y>

<25x^2+4y^2+20xy>-<4x^2+25y^2+20xy>

25x^2+4y^2+20xy-4x^2-25y^2-20xy

25x^2-4x^2+4y^2-25y^2+20xy-20xy

21x^2-21y^2=0

take 21 common

21(x^2+y^2)=0 then,

x^2+y^2=0

Step-by-step explanation:

I hope it will be helpful

Answered by rordivyam27
0

Answer:

hey I thought it may help you

Step-by-step explanation:

now thake this equation as -

(a+b)²- (b+a)² now solve it

(5x)²+( 2y)² - (2x)² + (5y)²

25x²+4y² - 4x² + 25y²

now solve it

25x²+4x²+4y²-25y²=0

29x²- 21y²= 0

it would helpful to u and plezzz follow me for more helps

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