Math, asked by Arpita7154, 8 months ago

(5x^2y^3)* (-y²z) × (-2x32yz7) x (-1/5xyz)

Answers

Answered by thapadenish462
2

Answer:

-4x^6y^7z^9

Step-by-step explanation:

=(5x^2y^3)×(-y^2z)×(-2x^32yz^7)×(-1/5xyz)

=(-5x^2y^5z)× (-4x^3yz^7)×(-1/5xyz)

=(-5 × -4 × - 1/5) (x^2+3+1 y^5+1+1 z 1+7+1)

= -4x^6y^7z^9

Similar questions