Question

(√5x+3)(5x+√5) solve with midle term splitting​

Answer 1

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(√5x+3)(5x+√5) solve with midle term splitting

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$= > (√5x+3)(5x+√5)$

$= > \sqrt{5x} (5x + \sqrt{5} ) + 3(5x + \sqrt{5} )$

$= > 5 \sqrt{5} {x}^{2} + 5x + 15x + 3 \sqrt{5}$

=>The equation is in the form of a quadratic equation whose highest degree is 2.

=>Here,midle term already splitted so we just take common and find factors .

=>15 can be also written as :

$\bold{\red{15 = 3 \times \sqrt{5} \sqrt{5}}}$

$= > 5x( \sqrt{5} x + 1) + 3 \sqrt{5} ( \sqrt{5} x + 1)$

$\bold{\boxed{= > (5x + 3 \sqrt{5} )( \sqrt{5} x + 1)}}$

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