5x - 3y = 1 , 2x + 5y = 19
Solve it by the method of substitution.
Answers
Answered by
49
Hey......^_^
➡ Using substitution method
◾ 5x - 3y = 1 ... 1st equation
2x + 5y = 19
,OR
x = {19 - 5y } ÷ 2
Substituting the value of x in 1st equation
5 { 19-5y}÷2 - 3y = 1
{95 - 25y} ÷ 2 -3y -1 = 0
{95 - 25y - 6y - 2 } ÷ 2 = 0
{93 - 31y } = 0
31y = 93
↪↪ y = 3
Therefore
x = {19 - 5×3} ÷ 2
x = {19-15} ÷ 2
↪↪ x = 2
✌Hope it helps
➡ Using substitution method
◾ 5x - 3y = 1 ... 1st equation
2x + 5y = 19
,OR
x = {19 - 5y } ÷ 2
Substituting the value of x in 1st equation
5 { 19-5y}÷2 - 3y = 1
{95 - 25y} ÷ 2 -3y -1 = 0
{95 - 25y - 6y - 2 } ÷ 2 = 0
{93 - 31y } = 0
31y = 93
↪↪ y = 3
Therefore
x = {19 - 5×3} ÷ 2
x = {19-15} ÷ 2
↪↪ x = 2
✌Hope it helps
NehaVaducool:
i m in class 10
there are two options Hindi nd Sanskrit
from which we have to select one
Better in what parameters ?
Which one is better to take ?
Ohkkk
I feel hindi
ohkk
thanks
My pleasure
Answered by
12
5x-3y=1...(i)
2x+5y=19....(ii)
From equation (i),we have
5x=1+3y
x=1+3y/5
substituting the value of x in (ii)
2x+5y=19
2*(1+3y/5)+5y=19
2+6y/5+5y=19
2+6y+25y/5=19
10+31y/5=19
10+31y=19*5
10+31y=95
31y=95-10
31y=85
y=85/31
on substituting y in equation (i) we get
5x-3y=1
5x-3(85/31)=1
5x-255/31=1
155x-255/31=1
155x-255=31
155x=31+255
155x=286
x=286/155
hence x=286/155 and y=85/31
may be it is helpful for you
2x+5y=19....(ii)
From equation (i),we have
5x=1+3y
x=1+3y/5
substituting the value of x in (ii)
2x+5y=19
2*(1+3y/5)+5y=19
2+6y/5+5y=19
2+6y+25y/5=19
10+31y/5=19
10+31y=19*5
10+31y=95
31y=95-10
31y=85
y=85/31
on substituting y in equation (i) we get
5x-3y=1
5x-3(85/31)=1
5x-255/31=1
155x-255/31=1
155x-255=31
155x=31+255
155x=286
x=286/155
hence x=286/155 and y=85/31
may be it is helpful for you
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